Let us consider this following equation
8x+5y=9
3x+2y=4
Solving this on traditional method will take more time… so here, we are solving it in cross multiplication method..
For this, 1st check whether the equation is in the correct order..
Eg
It must be in
Ax+By=c1…..(1)
Dx+Ey=c2…..(2) here, a,b,c1,d,e,c2 are any numbers..
Then 2nd step is taking coefficient of y from equation 2 is necessary.. always start with that number.
Ax+By=c1
Dx+Ey=c2
for getting numerator part first consider this highlighted part and start with E, ie. Coefficient of y in 2nd equation
And subtract those terms…
E*C1 – C2*B this is numerator part.
For getting denominator part
Ax+By=c1…..(1)
Dx+Ey=c2…..(2)
Consider this highlighted part & again start with E i.e. Coefficient of y in 2nd equation.
And subtract those terms
E*A – D*B this denominator part
Numerator part / denominator part
E*C1 – C2*B/ E*A – D*B
Solving this we will be getting X value then substituting in either (1) or (2) will get Y value.
Let's solve it with real time problem…
8x+5y=9 ……(1)
3x+2y=4 ……(2)
Numerator part
2*9 – 4*5 = -2
Denominator part
2*8 – 3*5 = 1
= -2/1 we will get the value of X as -2
X=-2 substituting this value in either (1) or (2) to get the value of Y= 5